B=7/5(j-3)

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Solution for B=7/5(j-3) equation: 



=7/5(B-3)

We move all terms to the left:

-(7/5(B-3))=0



Domain of the equation: 5(B-3))!=0

B∈R



We multiply all the terms by the denominator


-(7=0

We add all the numbers together, and all the variables

=0

B=0/1

B=0

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