B=8/3(j-7)

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Solution for B=8/3(j-7) equation: 



=8/3(B-7)

We move all terms to the left:

-(8/3(B-7))=0



Domain of the equation: 3(B-7))!=0

B∈R



We multiply all the terms by the denominator


-(8=0

We add all the numbers together, and all the variables

=0

B=0/1

B=0

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