B=9/5(j-78)

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Solution for B=9/5(j-78) equation:



=9/5(B-78)
We move all terms to the left:
-(9/5(B-78))=0
Domain of the equation: 5(B-78))!=0
B∈R
We multiply all the terms by the denominator
-(9=0
We add all the numbers together, and all the variables
=0
B=0/1
B=0

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