B=9/8(j-28)

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Solution for B=9/8(j-28) equation: 



=9/8(B-28)

We move all terms to the left:

-(9/8(B-28))=0



Domain of the equation: 8(B-28))!=0

B∈R



We multiply all the terms by the denominator


-(9=0

We add all the numbers together, and all the variables

=0

B=0/1

B=0

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