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=B(5-7B)
We move all terms to the left:
-(B(5-7B))=0
We add all the numbers together, and all the variables
-(B(-7B+5))=0
We calculate terms in parentheses: -(B(-7B+5)), so:We get rid of parentheses
B(-7B+5)
We multiply parentheses
-7B^2+5B
Back to the equation:
-(-7B^2+5B)
7B^2-5B=0
a = 7; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·7·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*7}=\frac{0}{14} =0 $$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*7}=\frac{10}{14} =5/7 $
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