BD=2(5a+1)

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Solution for BD=2(5a+1) equation: 



=2(5B+1)

We move all terms to the left:

-(2(5B+1))=0



We calculate terms in parentheses: -(2(5B+1)), so:

2(5B+1)

We multiply parentheses

10B+2

Back to the equation:

-(10B+2)



We get rid of parentheses

-10B-2=0

We move all terms containing B to the left, all other terms to the right

-10B=2

B=2/-10

B=-1/5

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