C(12)=40+3x

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Solution for C(12)=40+3x equation: 



(12)=40+3C

We move all terms to the left:

(12)-(40+3C)=0

We add all the numbers together, and all the variables

-(3C+40)+12=0

We get rid of parentheses

-3C-40+12=0

We add all the numbers together, and all the variables

-3C-28=0

We move all terms containing C to the left, all other terms to the right

-3C=28

C=28/-3

C=-9+1/3

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