C(12C+5)=7

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Solution for C(12C+5)=7 equation:


Simplifying
C(12C + 5) = 7

Reorder the terms:
C(5 + 12C) = 7
(5 * C + 12C * C) = 7
(5C + 12C2) = 7

Solving
5C + 12C2 = 7

Solving for variable 'C'.

Reorder the terms:
-7 + 5C + 12C2 = 7 + -7

Combine like terms: 7 + -7 = 0
-7 + 5C + 12C2 = 0

Factor a trinomial.
(-1 + -1C)(7 + -12C) = 0

Subproblem 1

Set the factor '(-1 + -1C)' equal to zero and attempt to solve: Simplifying -1 + -1C = 0 Solving -1 + -1C = 0 Move all terms containing C to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -1C = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -1C = 0 + 1 -1C = 0 + 1 Combine like terms: 0 + 1 = 1 -1C = 1 Divide each side by '-1'. C = -1 Simplifying C = -1

Subproblem 2

Set the factor '(7 + -12C)' equal to zero and attempt to solve: Simplifying 7 + -12C = 0 Solving 7 + -12C = 0 Move all terms containing C to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -12C = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -12C = 0 + -7 -12C = 0 + -7 Combine like terms: 0 + -7 = -7 -12C = -7 Divide each side by '-12'. C = 0.5833333333 Simplifying C = 0.5833333333

Solution

C = {-1, 0.5833333333}

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