C(Q)=100+10Q+5Q2q=7

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Solution for C(Q)=100+10Q+5Q2q=7 equation: 



()=100+10+52C=7

We move all terms to the left:

()-(100+10+52C)=0

We add all the numbers together, and all the variables

-(52C+110)+()=0

We add all the numbers together, and all the variables

-(52C+110)=0

We get rid of parentheses

-52C-110=0

We move all terms containing C to the left, all other terms to the right

-52C=110

C=110/-52

C=-2+3/26

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