C(p)=4(3p+25)

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Solution for C(p)=4(3p+25) equation: 



(C)=4(3C+25)

We move all terms to the left:

(C)-(4(3C+25))=0



We calculate terms in parentheses: -(4(3C+25)), so:

4(3C+25)

We multiply parentheses

12C+100

Back to the equation:

-(12C+100)



We get rid of parentheses

C-12C-100=0

We add all the numbers together, and all the variables

-11C-100=0

We move all terms containing C to the left, all other terms to the right

-11C=100

C=100/-11

C=-9+1/11

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