C(q)=100+2q2

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Solution for C(q)=100+2q2 equation: 



(C)=100+2C^2

We move all terms to the left:

(C)-(100+2C^2)=0

We get rid of parentheses

-2C^2+C-100=0

a = -2; b = 1; c = -100;
Δ = b2-4ac
Δ = 12-4·(-2)·(-100)
Δ = -799
Delta is less than zero, so there is no solution for the equation

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