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(C)=-5C^2+100C-80
We move all terms to the left:
(C)-(-5C^2+100C-80)=0
We get rid of parentheses
5C^2-100C+C+80=0
We add all the numbers together, and all the variables
5C^2-99C+80=0
a = 5; b = -99; c = +80;
Δ = b2-4ac
Δ = -992-4·5·80
Δ = 8201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-99)-\sqrt{8201}}{2*5}=\frac{99-\sqrt{8201}}{10} $$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-99)+\sqrt{8201}}{2*5}=\frac{99+\sqrt{8201}}{10} $
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