C(x)=1800(x2+4)1/3+900

Solution for C(x)=1800(x2+4)1/3+900 equation:

(C)=1800(C2+4)1/3+900

We move all terms to the left:

(C)-(1800(C2+4)1/3+900)=0

We add all the numbers together, and all the variables

-(1800(+C^2+4)1/3+900)+C=0

We multiply all the terms by the denominator


-(1800(+C^2+4)1+C*3+900)=0


We calculate terms in parentheses: -(1800(+C^2+4)1+C*3+900), so:

1800(+C^2+4)1+C*3+900

We multiply parentheses

1800C^2+C*3+7200+900

Wy multiply elements

1800C^2+3C+7200+900

We add all the numbers together, and all the variables

1800C^2+3C+8100

Back to the equation:

-(1800C^2+3C+8100)


We get rid of parentheses

-1800C^2-3C-8100=0

a = -1800; b = -3; c = -8100;
Δ = b2-4ac
Δ = -32-4·(-1800)·(-8100)
Δ = -58319991
Delta is less than zero, so there is no solution for the equation