C(x)=2x+40,x=13

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Solution for C(x)=2x+40,x=13 equation: 



(C)=2C+40.C=13

We move all terms to the left:

(C)-(2C+40.C)=0

We add all the numbers together, and all the variables

C-(+42C)=0

We get rid of parentheses

C-42C=0

We add all the numbers together, and all the variables

-41C=0

C=0/-41

C=0

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