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(C)=3C^2-18C+72.
We move all terms to the left:
(C)-(3C^2-18C+72.)=0
We get rid of parentheses
-3C^2+C+18C-72.=0
We add all the numbers together, and all the variables
-3C^2+19C-72=0
a = -3; b = 19; c = -72;
Δ = b2-4ac
Δ = 192-4·(-3)·(-72)
Δ = -503
Delta is less than zero, so there is no solution for the equation
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