C(x)=40x+1200

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Solution for C(x)=40x+1200 equation:



(C)=40C+1200
We move all terms to the left:
(C)-(40C+1200)=0
We get rid of parentheses
C-40C-1200=0
We add all the numbers together, and all the variables
-39C-1200=0
We move all terms containing C to the left, all other terms to the right
-39C=1200
C=1200/-39
C=-30+10/13

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