C(x)=40x+1200

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Solution for C(x)=40x+1200 equation: 



(C)=40C+1200

We move all terms to the left:

(C)-(40C+1200)=0

We get rid of parentheses

C-40C-1200=0

We add all the numbers together, and all the variables

-39C-1200=0

We move all terms containing C to the left, all other terms to the right

-39C=1200

C=1200/-39

C=-30+10/13

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