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(C)=4C^2-32C+128
We move all terms to the left:
(C)-(4C^2-32C+128)=0
We get rid of parentheses
-4C^2+C+32C-128=0
We add all the numbers together, and all the variables
-4C^2+33C-128=0
a = -4; b = 33; c = -128;
Δ = b2-4ac
Δ = 332-4·(-4)·(-128)
Δ = -959
Delta is less than zero, so there is no solution for the equation
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