C(x)=5000+20xI(x)=80x-0.1x2

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Solution for C(x)=5000+20xI(x)=80x-0.1x2 equation: 



(C)=5000+20C(C)=80C-0.1C^2

We move all terms to the left:

(C)-(5000+20C(C))=0

We add all the numbers together, and all the variables

C-(20CC+5000)=0

We get rid of parentheses

C-20CC-5000=0

We move all terms containing C to the left, all other terms to the right

C-20CC=5000

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