C+(c+2)+(c+4)=27

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Solution for C+(c+2)+(c+4)=27 equation:


Simplifying
C + (c + 2) + (c + 4) = 27

Reorder the terms:
C + (2 + c) + (c + 4) = 27

Remove parenthesis around (2 + c)
C + 2 + c + (c + 4) = 27

Reorder the terms:
C + 2 + c + (4 + c) = 27

Remove parenthesis around (4 + c)
C + 2 + c + 4 + c = 27

Reorder the terms:
2 + 4 + C + c + c = 27

Combine like terms: 2 + 4 = 6
6 + C + c + c = 27

Combine like terms: c + c = 2c
6 + C + 2c = 27

Solving
6 + C + 2c = 27

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + C + -6 + 2c = 27 + -6

Reorder the terms:
6 + -6 + C + 2c = 27 + -6

Combine like terms: 6 + -6 = 0
0 + C + 2c = 27 + -6
C + 2c = 27 + -6

Combine like terms: 27 + -6 = 21
C + 2c = 21

Add '-2c' to each side of the equation.
C + 2c + -2c = 21 + -2c

Combine like terms: 2c + -2c = 0
C + 0 = 21 + -2c
C = 21 + -2c

Simplifying
C = 21 + -2c

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