C+(c+2)+6=3c

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Solution for C+(c+2)+6=3c equation: 



+(C+2)+6=3C

We move all terms to the left:

+(C+2)+6-(3C)=0

We add all the numbers together, and all the variables

-3C+(C+2)+6=0

We get rid of parentheses

-3C+C+2+6=0

We add all the numbers together, and all the variables

-2C+8=0

We move all terms containing C to the left, all other terms to the right

-2C=-8

C=-8/-2

C=+4

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