C+(c+6)+(2(c+6))=258

Solution for C+(c+6)+(2(c+6))=258 equation:

+(C+6)+(2(C+6))=258

We move all terms to the left:

+(C+6)+(2(C+6))-(258)=0

We get rid of parentheses

C+(2(C+6))+6-258=0


We calculate terms in parentheses: +(2(C+6)), so:

2(C+6)

We multiply parentheses

2C+12

Back to the equation:

+(2C+12)


We add all the numbers together, and all the variables

C+(2C+12)-252=0

We get rid of parentheses

C+2C+12-252=0

We add all the numbers together, and all the variables

3C-240=0

We move all terms containing C to the left, all other terms to the right

3C=240

C=240/3

C=80