C+2(3c+1)=23

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Solution for C+2(3c+1)=23 equation:


Simplifying
C + 2(3c + 1) = 23

Reorder the terms:
C + 2(1 + 3c) = 23
C + (1 * 2 + 3c * 2) = 23
C + (2 + 6c) = 23

Reorder the terms:
2 + C + 6c = 23

Solving
2 + C + 6c = 23

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + C + -2 + 6c = 23 + -2

Reorder the terms:
2 + -2 + C + 6c = 23 + -2

Combine like terms: 2 + -2 = 0
0 + C + 6c = 23 + -2
C + 6c = 23 + -2

Combine like terms: 23 + -2 = 21
C + 6c = 21

Add '-6c' to each side of the equation.
C + 6c + -6c = 21 + -6c

Combine like terms: 6c + -6c = 0
C + 0 = 21 + -6c
C = 21 + -6c

Simplifying
C = 21 + -6c

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