C+2c(1-c)=10-3c

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Solution for C+2c(1-c)=10-3c equation: 


Simplifying
C + 2c(1 + -1c) = 10 + -3c
C + (1 * 2c + -1c * 2c) = 10 + -3c
C + (2c + -2c2) = 10 + -3c

Solving
C + 2c + -2c2 = 10 + -3c

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-2c' to each side of the equation.
C + 2c + -2c + -2c2 = 10 + -3c + -2c

Combine like terms: 2c + -2c = 0
C + 0 + -2c2 = 10 + -3c + -2c
C + -2c2 = 10 + -3c + -2c

Combine like terms: -3c + -2c = -5c
C + -2c2 = 10 + -5c

Add '2c2' to each side of the equation.
C + -2c2 + 2c2 = 10 + -5c + 2c2

Combine like terms: -2c2 + 2c2 = 0
C + 0 = 10 + -5c + 2c2
C = 10 + -5c + 2c2

Simplifying
C = 10 + -5c + 2c2

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