C+3(6-x)=20

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Solution for C+3(6-x)=20 equation: 



+3(6-C)=20

We move all terms to the left:

+3(6-C)-(20)=0

We add all the numbers together, and all the variables

3(-1C+6)-20=0

We multiply parentheses

-3C+18-20=0

We add all the numbers together, and all the variables

-3C-2=0

We move all terms containing C to the left, all other terms to the right

-3C=2

C=2/-3

C=-2/3

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