C+3-2c-1-3c=2

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Solution for C+3-2c-1-3c=2 equation:


Simplifying
C + 3 + -2c + -1 + -3c = 2

Reorder the terms:
3 + -1 + C + -2c + -3c = 2

Combine like terms: 3 + -1 = 2
2 + C + -2c + -3c = 2

Combine like terms: -2c + -3c = -5c
2 + C + -5c = 2

Add '-2' to each side of the equation.
2 + C + -2 + -5c = 2 + -2

Reorder the terms:
2 + -2 + C + -5c = 2 + -2

Combine like terms: 2 + -2 = 0
0 + C + -5c = 2 + -2
C + -5c = 2 + -2

Combine like terms: 2 + -2 = 0
C + -5c = 0

Solving
C + -5c = 0

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '5c' to each side of the equation.
C + -5c + 5c = 0 + 5c

Combine like terms: -5c + 5c = 0
C + 0 = 0 + 5c
C = 0 + 5c
Remove the zero:
C = 5c

Simplifying
C = 5c

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