C+4c+(C+8)=20

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Solution for C+4c+(C+8)=20 equation:


Simplifying
C + 4c + (C + 8) = 20

Reorder the terms:
C + 4c + (8 + C) = 20

Remove parenthesis around (8 + C)
C + 4c + 8 + C = 20

Reorder the terms:
8 + C + C + 4c = 20

Combine like terms: C + C = 2C
8 + 2C + 4c = 20

Solving
8 + 2C + 4c = 20

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + 2C + -8 + 4c = 20 + -8

Reorder the terms:
8 + -8 + 2C + 4c = 20 + -8

Combine like terms: 8 + -8 = 0
0 + 2C + 4c = 20 + -8
2C + 4c = 20 + -8

Combine like terms: 20 + -8 = 12
2C + 4c = 12

Add '-4c' to each side of the equation.
2C + 4c + -4c = 12 + -4c

Combine like terms: 4c + -4c = 0
2C + 0 = 12 + -4c
2C = 12 + -4c

Divide each side by '2'.
C = 6 + -2c

Simplifying
C = 6 + -2c

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