C-3-5-3c=-(-c+3)-(c-5)

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Solution for C-3-5-3c=-(-c+3)-(c-5) equation: 



-3-5-3C=-(-C+3)-(C-5)

We move all terms to the left:

-3-5-3C-(-(-C+3)-(C-5))=0

We add all the numbers together, and all the variables

-3C-(-(-1C+3)-(C-5))-3-5=0

We add all the numbers together, and all the variables

-3C-(-(-1C+3)-(C-5))-8=0



We calculate terms in parentheses: -(-(-1C+3)-(C-5)), so:

-(-1C+3)-(C-5)

We get rid of parentheses

1C-C-3+5

We add all the numbers together, and all the variables

2

Back to the equation:

-(2)



We add all the numbers together, and all the variables

-3C-10=0

We move all terms containing C to the left, all other terms to the right

-3C=10

C=10/-3

C=-3+1/3

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