C49-(2c+4)=4(c+6)+

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Solution for C49-(2c+4)=4(c+6)+ equation: 



49-(2C+4)=4(C+6)+

We move all terms to the left:

49-(2C+4)-(4(C+6)+)=0

We get rid of parentheses

-2C-(4(C+6)+)-4+49=0



We calculate terms in parentheses: -(4(C+6)+), so:

4(C+6)+

We add all the numbers together, and all the variables

4(C+6)

We multiply parentheses

4C+24

Back to the equation:

-(4C+24)



We add all the numbers together, and all the variables

-2C-(4C+24)+45=0

We get rid of parentheses

-2C-4C-24+45=0

We add all the numbers together, and all the variables

-6C+21=0

We move all terms containing C to the left, all other terms to the right

-6C=-21

C=-21/-6

C=3+1/2

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