C=(2a-3b)/2

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Solution for C=(2a-3b)/2 equation: 


x in (-oo:+oo)

C = (2*a-(3*b))/2 // - (2*a-(3*b))/2

C-((2*a-(3*b))/2) = 0

C-((2*a-3*b)/2) = 0

(-1*(2*a-3*b))/2+C = 0

(-1*(2*a-3*b))/2+(2*C)/2 = 0

2*C-1*(2*a-3*b) = 0

2*C-2*a+3*b = 0

(2*C-2*a+3*b)/2 = 0

(2*C-2*a+3*b)/2 = 0 // * 2

2*C-2*a+3*b = 0

x belongs to the empty set

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