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=(5(-32))/C
We move all terms to the left:
-((5(-32))/C)=0
Domain of the equation: C)!=0We multiply all the terms by the denominator
C!=0/1
C!=0
C∈R
-((5(-32))=0
We calculate terms in parentheses: -((5(-32)), so:We add all the numbers together, and all the variables
(5(-32)
We add all the numbers together, and all the variables
Back to the equation:
-()
=0
C=0/1
C=0
Równanie nie ma rozwiązania
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