C=100+3q+7q2

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Solution for C=100+3q+7q2 equation: 



=100+3C+7C^2

We move all terms to the left:

-(100+3C+7C^2)=0

We get rid of parentheses

-7C^2-3C-100=0

a = -7; b = -3; c = -100;
Δ = b2-4ac
Δ = -32-4·(-7)·(-100)
Δ = -2791
Delta is less than zero, so there is no solution for the equation

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