C=2(3f-32)

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Solution for C=2(3f-32) equation: 



=2(3C-32)

We move all terms to the left:

-(2(3C-32))=0



We calculate terms in parentheses: -(2(3C-32)), so:

2(3C-32)

We multiply parentheses

6C-64

Back to the equation:

-(6C-64)



We get rid of parentheses

-6C+64=0

We move all terms containing C to the left, all other terms to the right

-6C=-64

C=-64/-6

C=10+2/3

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