C=40/3x+20,R=15x

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Solution for C=40/3x+20,R=15x equation: 



=40/3C+20.=15C

We move all terms to the left:

-(40/3C+20.)=0



Domain of the equation: 3C+20.)!=0

C∈R



We add all the numbers together, and all the variables

-(40/3C+20)=0

We get rid of parentheses

-40/3C-20=0

We multiply all the terms by the denominator


-20*3C-40=0

Wy multiply elements

-60C-40=0

We move all terms containing C to the left, all other terms to the right

-60C=40

C=40/-60

C=-2/3

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