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=4C^2-3C+7
We move all terms to the left:
-(4C^2-3C+7)=0
We get rid of parentheses
-4C^2+3C-7=0
a = -4; b = 3; c = -7;
Δ = b2-4ac
Δ = 32-4·(-4)·(-7)
Δ = -103
Delta is less than zero, so there is no solution for the equation
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