C=5/2(k-57)

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Solution for C=5/2(k-57) equation: 



=5/2(C-57)

We move all terms to the left:

-(5/2(C-57))=0



Domain of the equation: 2(C-57))!=0

C∈R



We multiply all the terms by the denominator


-(5=0

We add all the numbers together, and all the variables

=0

C=0/1

C=0

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