C=5/3(k-52)

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Solution for C=5/3(k-52) equation:



=5/3(C-52)
We move all terms to the left:
-(5/3(C-52))=0
Domain of the equation: 3(C-52))!=0
C∈R
We multiply all the terms by the denominator
-(5=0
We add all the numbers together, and all the variables
=0
C=0/1
C=0

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