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=5/9(C41)
We move all terms to the left:
-(5/9(C41))=0
Domain of the equation: 9C41)!=0We add all the numbers together, and all the variables
C!=0/1
C!=0
C∈R
-(+5/9C41)=0
We get rid of parentheses
-5/9C41=0
We multiply all the terms by the denominator
-5!=0
There is no solution for this equation
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