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=5/9C(212-32)
We move all terms to the left:
-(5/9C(212-32))=0
Domain of the equation: 9C(212-32))!=0We add all the numbers together, and all the variables
C∈R
-(5/9C180)=0
We get rid of parentheses
-5/9C180=0
We multiply all the terms by the denominator
-5!=0
There is no solution for this equation
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