C=5z+15;H=6z+10

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Solution for C=5z+15;H=6z+10 equation: 



=5C+15=6C+10

We move all terms to the left:

-(5C+15)=0

We get rid of parentheses

-5C-15=0

We move all terms containing C to the left, all other terms to the right

-5C=15

C=15/-5

C=-3

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