C=6/5(k-35)

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Solution for C=6/5(k-35) equation: 


x in (-oo:+oo)

C = (6/5)*(k-35) // - (6/5)*(k-35)

C-((6/5)*(k-35)) = 0

(-6/5)*(k-35)+C = 0

C-6/5*(k-35) = 0

C-6/5*(k-35) = 0

C-6/5*k+42 = 0

C-6/5*k+42 = 0

x belongs to the empty set

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