C=8g(1.50g+195)=

Solution for C=8g(1.50g+195)= equation:

=8C(1.50C+195)=

We move all terms to the left:

-(8C(1.50C+195))=0


We calculate terms in parentheses: -(8C(1.50C+195)), so:

8C(1.50C+195)

We multiply parentheses

8C^2+1560C

Back to the equation:

-(8C^2+1560C)


We get rid of parentheses

-8C^2-1560C=0

a = -8; b = -1560; c = 0;
Δ = b2-4ac
Δ = -15602-4·(-8)·0
Δ = 2433600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2433600}=1560$
$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1560)-1560}{2*-8}=\frac{0}{-16}
=0
$
$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1560)+1560}{2*-8}=\frac{3120}{-16}
=-195
$