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=9C^2+48C+64
We move all terms to the left:
-(9C^2+48C+64)=0
We get rid of parentheses
-9C^2-48C-64=0
a = -9; b = -48; c = -64;
Δ = b2-4ac
Δ = -482-4·(-9)·(-64)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$C=\frac{-b}{2a}=\frac{48}{-18}=-2+2/3$
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