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cos(6*x-((2*x)/2)) = 0
cos(6*x-x) = 0
cos(6*x-((2*x)/2)) = 0 <=> 6*x-((2*x)/2) = pi*k_1+pi/2 i k_1 należy do I
t_1 = pi*k_1+pi/2
6*x-t_1-((2*x)/2) = 0
6*x-t_1-x = 0
5*x-t_1 = 0 // + t_1
5*x = t_1 // : 5
x = t_1/5
x = pi*k_1+pi/2/5 i k_1 należy do I
x = pi*k_1+pi/2/5
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