Cos(8x)+cos(4x)+2cos(2x)=0

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Solution for Cos(8x)+cos(4x)+2cos(2x)=0 equation:


Simplifying
Cos(8x) + cos(4x) + 2cos(2x) = 0

Remove parenthesis around (8x)
osC * 8x + cos(4x) + 2cos(2x) = 0

Reorder the terms for easier multiplication:
8osC * x + cos(4x) + 2cos(2x) = 0

Multiply osC * x
8osxC + cos(4x) + 2cos(2x) = 0

Remove parenthesis around (4x)
8osxC + cos * 4x + 2cos(2x) = 0

Reorder the terms for easier multiplication:
8osxC + 4cos * x + 2cos(2x) = 0

Multiply cos * x
8osxC + 4cosx + 2cos(2x) = 0

Remove parenthesis around (2x)
8osxC + 4cosx + 2cos * 2x = 0

Reorder the terms for easier multiplication:
8osxC + 4cosx + 2 * 2cos * x = 0

Multiply 2 * 2
8osxC + 4cosx + 4cos * x = 0

Multiply cos * x
8osxC + 4cosx + 4cosx = 0

Reorder the terms:
4cosx + 4cosx + 8osxC = 0

Combine like terms: 4cosx + 4cosx = 8cosx
8cosx + 8osxC = 0

Solving
8cosx + 8osxC = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8osxC' to each side of the equation.
8cosx + 8osxC + -8osxC = 0 + -8osxC

Combine like terms: 8osxC + -8osxC = 0
8cosx + 0 = 0 + -8osxC
8cosx = 0 + -8osxC
Remove the zero:
8cosx = -8osxC

Divide each side by '8osx'.
c = -1C

Simplifying
c = -1C

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