D/5+3D-10=(1/3)d+33

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Solution for D/5+3D-10=(1/3)d+33 equation: 



/5+3-10=(1/3)D+33

We move all terms to the left:

/5+3-10-((1/3)D+33)=0



Domain of the equation: 3)D+33)!=0

D!=0/1

D!=0

D∈R



We add all the numbers together, and all the variables

-((+1/3)D+33)+3-10+/5=0

We add all the numbers together, and all the variables

-((+1/3)D+33)-7+/5=0

We calculate fractions


()/3D+33)*5)+(*3)D+33))/3D+33)*5)-7=0

We add all the numbers together, and all the variables

()/3D+33)*5)+0D+33))/3D+33)*5)-7=0

We calculate fractions


(()*3D)/9D^2+33*5)+0D+33))*3D)/9D^2=0

We multiply all the terms by the denominator


(()*3D)+33*5)+0D+33))*3D)=0



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495D^2+(()*3D)=0



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