D=(a+3b)/2c

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Solution for D=(a+3b)/2c equation: 


x in (-oo:+oo)

D = c*((a+3*b)/2) // - c*((a+3*b)/2)

D-(c*((a+3*b)/2)) = 0

(-1*c*(a+3*b))/2+D = 0

(-1*c*(a+3*b))/2+(2*D)/2 = 0

2*D-1*c*(a+3*b) = 0

2*D-3*b*c-(a*c) = 0

(2*D-3*b*c-(a*c))/2 = 0

(2*D-3*b*c-(a*c))/2 = 0 // * 2

2*D-3*b*c-(a*c) = 0

x belongs to the empty set

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