D=-16t2+196

Solution for D=-16t2+196 equation:

=-16D^2+196

We move all terms to the left:

-(-16D^2+196)=0

We get rid of parentheses

16D^2-196=0

a = 16; b = 0; c = -196;
Δ = b2-4ac
Δ = 02-4·16·(-196)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$D_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$D_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$D_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-112}{2*16}=\frac{-112}{32}
=-3+1/2
$
$D_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+112}{2*16}=\frac{112}{32}
=3+1/2
$