D=0.5t(3.5t-28.25)

Solution for D=0.5t(3.5t-28.25) equation:

=0.5D(3.5D-28.25)

We move all terms to the left:

-(0.5D(3.5D-28.25))=0


We calculate terms in parentheses: -(0.5D(3.5D-28.25)), so:

0.5D(3.5D-28.25)

We multiply parentheses

0D^2-0D

We add all the numbers together, and all the variables

D^2-1D

Back to the equation:

-(D^2-1D)


We get rid of parentheses

-D^2+1D=0

We add all the numbers together, and all the variables

-1D^2+D=0

a = -1; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-1)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$D_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$D_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$D_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-1}=\frac{-2}{-2}
=1
$
$D_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-1}=\frac{0}{-2}
=0
$