D=2p-3/3p-1

Solution for D=2p-3/3p-1 equation:

=2D-3/3D-1

We move all terms to the left:

-(2D-3/3D-1)=0


Domain of the equation: 3D-1)!=0

D∈R


We get rid of parentheses

-2D+3/3D+1=0

We multiply all the terms by the denominator


-2D*3D+1*3D+3=0

Wy multiply elements

-6D^2+3D+3=0

a = -6; b = 3; c = +3;
Δ = b2-4ac
Δ = 32-4·(-6)·3
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$D_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$D_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$D_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-9}{2*-6}=\frac{-12}{-12}
=1
$
$D_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+9}{2*-6}=\frac{6}{-12}
=-1/2
$