E/4x-6x+8x+40=0

Solution for E/4x-6x+8x+40=0 equation:

/4E-6E+8E+40=0


Domain of the equation: 4E!=0

E!=0/4

E!=0

E∈R


We add all the numbers together, and all the variables

2E+/4E+40=0

We multiply all the terms by the denominator


2E*4E+40*4E+=0

We add all the numbers together, and all the variables

2E*4E+40*4E=0

Wy multiply elements

8E^2+160E=0

a = 8; b = 160; c = 0;
Δ = b2-4ac
Δ = 1602-4·8·0
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$E_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$E_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$E_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-160}{2*8}=\frac{-320}{16}
=-20
$
$E_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+160}{2*8}=\frac{0}{16}
=0
$